int ia[2] -> Double

[Unregistered]

I would like to place 2 UINT32's into a Double:

double d = 0;
unsigned int ia[2] = {0xdeadbeef, 0xcafefeed};

d = (double) ( (double)ia[0] | ((double)ia[1]<<32) );

However, this does not compile:

error C2296: '<<' : illegal, left operand has type 'double'

My input is a byte or integer stream. My output has to be a double.

How can I accomplish this?

J0xEFF

[Salem]

Try

union {
  double d;
  unsigned int ia[2];
} foo;

foo.ia[0] = 0xdeadbeef;
foo.ia[1] = 0xcafefeed;
cout << foo.d;

But you need to watch out for byte ordering

[swoopy]

One way is (this will give you a pointer to a double):

double *d;
unsigned int ia[2] = {0xdeadbeef, 0xcafefeed};

d = (double *) ia;
cout << "d:" << *d << endl;

Or another way is:

double *p;
double d = 0;
unsigned int ia[2] = {0xdeadbeef, 0xcafefeed};

p = (double *) ia;
d = *p;
cout << "d:" << d << endl;

[Dual-Catfish]

What about 0xBADF00D?

[swoopy]

>What about 0xBADF00D?

hehe, good one !