Thread: iff statement

the code is

// Hex Code Finder
// Created by Daniel Strong
// Special thanks to "cecildasquid" and "Gamer Tazer"
// Feel free to edit this and redistribute this. but you Must leave the above lines there! exactly how they are!
#include <iostream>
#include <string>
#include <stdlib.h>
#include <windows.h>
using namespace std;

int main()
{
string input,output;
//Pastels -word to hex
char snow[] = "#fffafa";
char ghostwhite[] = "#f8f8ff";
char whitesmoke[] = "#f5f5f5";
char grainsboro[] = "#dcdcdc";

//Pastels - hex to word
char fffafa[] = "snow";
char f8f8ff[] = "ghost white";
char f5f5f5[] = "white smoke";
char dcdcdc[] = "grainsboro";



cout << "Type in a Color to reveal its Hexcode." << endl ;
cout << " -or- Type in a Hexcode to reveal its Color." << endl ;
cout << " -or- Type in all to view all colors indexed." << endl ;
cout << endl ;
cout << " WARNING: when you type in a color make sure it is all" << endl ;
cout << " lowercase and has no spaces if the color has a space in it" << endl ;
cout << " just combine it. i.e. - 2 words is 2words" << endl ;
cout << endl ;
cout << " WARNING: make sure when you type in a hexcode that it" << endl ;
cout << " does not have the # symbol in it i.e. - #ffffff is ffffff" << endl ;
cin >> input;

if(input == "snow")
output = snow;
else if(input == "ghostwhite")
output = ghostwhite;
else if(input == "whitesmoke")
output = whitesmoke;
else if(input == "grainsboro")
output = grainsboro;


cout << "The Hexcode for the color " << input << " is " << output << endl ;
Sleep(5000);


else if(input == "fffafa")
output = fffafa;
else if(input == "f8f8ff")
output = f8f8ff;
else if(input == "f5f5f5")
output = f5f5f5;
else if(input == "dcdcdc")
output = dcdcdc;


cout << "The color of the Hexcode #" << input << " is " << output << endl ;
Sleep(5000);

cin.get();
return 0;
}

when i compile it and i input a hex code varible. after all the if statements at the cout its trys to do the first cout but has no output, then it goes thru the scond list of else ifs and finds an output os it makes my complete sentence. how can i make it so it wont display the firts cout message after the first set of ifs. when i put in a varible that corosponds with the second cout. did you get what im saying?

Wait no... now I see what you're probably saying.... try this....

PHP Code:

if(input == "snow") {
output = snow;
cout << "The Hexcode for the color " << input << " is " << output << endl ; 
Sleep(5000);
}
else if(input == "ghostwhite") {
output = ghostwhite; 
cout << "The Hexcode for the color " << input << " is " << output << endl ; 
Sleep(5000); 
}
else if(input == "whitesmoke") {
output = whitesmoke; 
cout << "The Hexcode for the color " << input << " is " << output << endl ; 
Sleep(5000); 
}
else if(input == "grainsboro") {
output = grainsboro; 
cout << "The Hexcode for the color " << input << " is " << output << endl ; 
Sleep(5000); 
} 


and so on...........


(me likes these PHP tags!)

though that is a bit obtuse... however I suppose it's ok to do in this little program

doob knows wut im trying to do, but i dont want to put that under each if statement. whats that thing about switches, wut r they and wut do they do (im newb to c++) u will hae all standard hex codes in this, theres ALOT. this is nothing close to bening done, well it is, but i still havta add a bunch more hex codes