Thread: Parse Error At End Of Input?!?!?!?!?!

What does that mean!!! I have saerch hign and low all throughout my code and found nuthing. I just cannot figure out why this is happening to me. Here is my code. Oh and it would be nice to also explain exactly what a parse error at end of input is because on other message boards people just give your awnsers and don't really help you to know why it is happening so u can fix it yourself next time.

Code:

#include <iostream.h>
#include <stdlib.h>
char word[502]; 
int decimal[502];
void binary();
int main()
{   char word[502]; 
    int decimal[502]; 
     cout<<"\nPlease Input Some Text\n";
     cin>>word;
     cout<<"\nThis Is Your Text In ASCII Decimals\n";
    for(int a=0;a<502;a++) 
    {decimal[a]=int(word[a]);
      cout<<decimal[a];}
      cout<<"This Is Your Text In Binary Numbers";
      binary();
       


      cout<<"\n\n Thats About It\n\n";
      system("PAUSE");
      return 0;
}

void binary()
{     char letter;
      int len, ascii, binary[8], total;
   
      len = strlen(word);  /* get the number of characters in entry. */
   /* this loop is executed for each letter in the string. */
   for(int i = 0; i<len; i++)
   {
      total = 0;
      letter = word[i]; /* store the first letter */
      ascii = letter;    /* put that letter into an int, so we can 
                            see its ASCII number */ 
      while(ascii>0) /* This while loop converts the ASCII # into binary,
                        stores it backwards into the binary array. */
      {
         /* To get the binary code one must take the decimal number in
            question, take it and divide it by two repeatedly, save
            the remainder (which will become the binary number), save
            the whole number, divide by two, and repeat the whole
            process until 0 is reached.  This if-else statement serves
            this functionality, by getting the remainder of the ascii
            code, storing it in the array and then dividing the int
            ascii by two */
         if((ascii%2)==0)
         {
            binary[total] = 0;
            ascii = ascii/2;
            total++; /* increasing by one each time will yeild the
                        number of numbers in the array. */
         }
         else
         {
            binary[total] = 1;
            ascii = ascii/2;
            total++;
         }
      }
      total--; /* due to data type factors, the program will actually
                  add a 0 at the end of the array that is not supposed
                  to be there, decrementing total will solve this
                  problem, as that 0 will not be displayed. */
      /* this while loop displays the binary code for that letter. */
      while(total>=0)
      {
         cout<<binary[total];
         total--;
      }}

by the way I am using dev-c++ version ummm 4. sumthing?

This is what I noticed right off:

Code:

char word[502]; 
int decimal[502];
void binary();
int main()
{   char word[502]; 
    int decimal[502];

You have redifined your variabled in main. This has the effect of masking your global variables so when you input to word you are inputting into the local definitions. Try removing the second def's.

Try adding one more } (end bracket) at the end of your binary function. You had left one out, I did that and the prog compiled and ran fine.