Get an int from a file

[Okiesmokie]

Does anyone here know how to get an int from a file?
What i mean is, take some numbers that are in a file, and store them in an int variable. when i try to go:

int buffer;
file.getline(buffer, 10);

it gives me some error about cannot convert type blah blah

and when i try to go:

char buffer[11];
file.getline((int)buffer, 10);

it gives me the same error =[

[SilentStrike]

file >> buffer;

?

Or there is a series of ints? Or what?

[Okiesmokie]

its a series of ints, like this:

00|01|02 etc..

[|deep|]

If you have some input like
00|01|02 then you cannot use it. Instead take the whole thing into an array and then separate the integers.
[CODE]
int main()
{
ifstream inFile;
inFile.open("c:\\deneme.txt");
char some[100];
inFile>>some;
//Take integers out of it
//Do something
return 0;
}

[vasanth]

Ok is this anything to do with th www.cpp-home.com contest..



Well in text text file everyting is stored as char...

And buffer has to be of type char and not int.. It will not work if it is int.. What you can do is... Get the ASCII value of the char..

char buffer;
file.get(buffer);
int ascii=buffer;



so now in the ascii variable, value the ASCII value of the character is stored.. The ascii value for numbers 0,1 to 9 i think starts from 49, 50 etc etc.. So you can use an if statement like

int array[100];

if(ascii==49)
array[1]=0;

if(ascii==50)
array[1]=1;



and so on.. Now you get the numbers as integers in the array.. If you have any doubts about this.. Post a reply i will sort it out for you...

Bye

[swoopy]

Is the file text? If yes and the integers are the same length, then use could:

   char buffer[3];
   int value;

   in.getline(buffer,3);
   value = atoi(buffer);
   in.getline(buffer,3);
   value = atoi(buffer);
   in.getline(buffer,3);
   value = atoi(buffer);

[Unregistered]

or use '|' as the delimiter for getline() instead of the default '\n'. That way you may have integers other than 2 digits that can still be read in successfully. If each line has 4 integers separated by a | and then the last integer is followed by a '\n', then use getline with '|' three times in a row and getline with a '\n' just once each loop through. If there are no '\n' in the file and it is all | separated then you don't need to do even that.

If all you know is that the file is | separated but don't know how many integers per line, and don't know if there are new line char in the section of data being analyzed, then you need to read in char by char looking for any separaters.

getline() combined with atoi() can be very flexible.

[Okiesmokie]

yes, i am using | as the deliminator, i was just writing off of memory as i was not on the computer that has my files on it.

what does atoi() do?

[Sorensen]

>what does atoi() do?

It converts strings to ints, but if you just want to read the first x number of ints from a file that are seperated by non-digit characters, you can use istreams inbuilt type checking, and do something like -

#include <iostream> 

using namespace std; 

int main() 
{
	const int count = 3;
	int a[count];
	int c=0;
	
	while (c<3)
	{
		cin >>a[c++];
		if(cin.fail())
		{
			cin.clear();
			cin.ignore();
			--c;
		}
	}

	cout << a[0] <<' '<<a[1]<<' ' << a[2];
	
	return 0;

}

This'll read the first 3 ints from cin (regardless of what is entered). Something similar will work for any number of ints or an ifstream in place of cin.

[Okiesmokie]

yea, but i dont want to use cin, i am trying to do file i/o

[Sorensen]

Then replace cin with your file i/o object. They are interchangable as both are are derived from the same base class.

[Flikm]

char delete;

while( delete != '\n' ){
    file >> myint;
    file.get( delete );
}

thisll get the number, eat the |, and loop until the new line.