Thread: concatenating integer to string

Hi guys!
I'm facing a problem that I would to concatenate integer to string, so I did:

Code:

int count=5;
string tmp= "";
tmp+=count;

it's wrong ! because the solution included also '0' in tmp+, mean:

Code:

int count=5;
string tmp= "";
tmp+=count+ '0';

what does + '0' mean in that case? why I'm using that sign?

any help please?

Oh... maybe adding a '0' to an integer is to add an '0' to an integer? Just maybe?

string isn't a data type. You want char* or char[n], which is an array of characters.

You can try sprintf to put the int into the character array.

Originally Posted by catacombs

string isn't a data type. You want char* or char[n], which is an array of characters.

Nope... in STL there is a class called basic_string and an alias called string. They are in namespace std (you need to include string header)... Notice this question was posted in C++ Programming board (not C).

RyanC, to help you answer your own question, here's a test:

Code:

$ g++ -xc++ -include iostream - <<EOF
int main() { int x = '0'; std::cout << x << std::endl; }
EOF
$ ./a.out
48

Hope it helps.

Originally Posted by flp1969

Nope... in STL there is a class called basic_string and an alias called string. They are in namespace std (you need to include string header)... Notice this question was posted in C++ Programming board (not C).

:facepalm:

Thanks. I didn't see the C++ tag.

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