Hello,
I need to convert a string into a large number (I am using double because it has to have decimal places)
Can someone please tell me why when I pass inCode:double ConvertStringToDouble(string s) { try { double d = 0.0d; d = stod(s); return d; } catch (exception ex) { return -1; } }
string mystr = "2532068"
it comes out as
2.53207e+06
Thanks in advance!
The conversion went fine, but you're seeing the result expressed in scientific notation. To change that behavior, you can pass a flag to the output stream, e.g.:
Code:std::string num("2532068"); double result = std::stod(num); std::cout << std::fixed << result << std::endl;
Last edited by Guest; 05-11-2018 at 05:19 PM.
By the way, 0.0 is a double constant; there's no need to add a non-standard d suffix, although in that part you don't even need the variable named d because you could just return stod(s).
Note that since you are returning -1 on conversion failure, you have no way to determine if a value of -1 is an error or a valid conversion, so this presupposes that in your context, -1 is never a valid value.
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
