I simply wanted to do this:
char y = “ “;
It wouldn’t compile using clang and c++14. I got the error ‘cannot initialize a variable of type ‘char’ with an Ivalue of type ‘const char’ ‘
1. What’s the default value of a char? Is it random just like int?
2. How should you initialize a char?
3. Can you please explain what an Ivalue is?
Double quotes make a string. Single quotes make a char. Remember that distinction, it's important.
1) C++ has no default values for the fundamental types. Only exception: When global, they are initialized to numerical zero.
2) However you wish, provided that it suits your needs and that it doesn't break your algorithms.
3) "lvalue" and "rvalue" are C++ jargon that describe the operands of an assignment. "lvalue" stands for "left value", meaning the operand on the left side of the assignment. "lvalues" must not be constant (otherwise, how could you assign to them). "rvalue" stands for "right value", meaning the operand on the right side. "rvalues" can be anything from constants, to variables. An rvalue is usually associated with the temporary result of an operation, such as:
in this example, a is an "lvalue" while "b*3 + 2" is an "rvalue".Code:a = b*3 + 2;
Devoted my life to programming...
When static they are initialised to 0 alsoOriginally Posted by GReaper
2) All of the following initialize a char variable to 0:
Code:char a{}; char b = '\0'; char c = 0; char d = char(); char e(0); char f('\0'); char g{0}; char h{'\0'};
It is too clear and so it is hard to see.
A dunce once searched for fire with a lighted lantern.
Had he known what fire was,
He could have cooked his rice much sooner.
Thanks
You can use c[i]= '\0' or simply c[i] = (char) 0.
The null/empty char is simply a value of zero, but can also be represented as a character with an escaped zero.
