While I'm toying with the language this weekend, is there anyway to do this:
or thisCode:LearnTrick("Roll Over", 10, 10);
if the function is prototyped asCode:LearnTrick(Trick("Roll Over", 10, 10));
and a Trick is:Code:LearnTrick(Trick);
Code:struct Trick { string name; int fatigue; int hunger; };
I know I could use a class with a constructor for this, but is there any way to have a struct be pieced together in a function argument?
A struct can have a constructor as well, much like a class. A struct is simply a class that has membership default to public rather than private in C++.
This won't do. The object Trick has a lifetime scope of that function call! And besides that, who is calling LearnTrick? Trick itself??LearnTrick(Trick("Roll Over", 10, 10));
Use them separately. If you need Trick to be declared in a larger scope but cannot teach it something just yet, declare Trick, and in main(), call Trick.LearnTrick("Roll Over", 10, 10));
Otherwise, if you are declaring and teaching at the same time, do Trick("Roll Over", 10, 10);
Code:#include <cmath> #include <complex> bool euler_flip(bool value) { return std::pow ( std::complex<float>(std::exp(1.0)), std::complex<float>(0, 1) * std::complex<float>(std::atan(1.0) *(1 << (value + 2))) ).real() < 0; }
No LearnTrick is a member function of a critter. It learns a Trick, which is added to a private array of tricks it has. Trick is a struct that contains a few ints and a string.
Sil, so Trick::Trick() will work?
cool.
It worked!
Thanks.
