Thread: length of array

I have an array with an unknown number of elements and want to know ne number of entries.
Here's my code:

Code:

#include <iostream>
#include <cmath>
#include <cstdio>


using namespace std;


class nvec{


	private:
		double *a;
		int length;


	public:
		nvec(int size, double*p)
		{
			length = size;
			a = new double [length];
			for(int i = 0;i<length;i++)
			{
				a[i] = p[i];
			}
		}
		//~nvec();
		double Len(void);
};
double nvec::Len(void)
{
double length = sizeof(a)/sizeof(double);
return length;
}
int main()
{
double t[]={2.,9.,12.,1.,113.};
nvec A(sizeof(t)/sizeof(double),t);
A.Print();
cout<<" :"<<A.Len()<<endl;
return 0;
}

However, I only get 1 as the length of the array. I guess this is because sizeof gives me just the memory of one entry.
What would be the correct way to accomplish what I try?

It's working. Thanks for your help.

Note that sizeof(array) returns the total size of array in bytes only if the array is statically allocated. For dynamically allocated arrays, the sizeof() only gives you the size of pointer.

BTW. In C++ raw pointers shouldn't be used. There are much better alternatives like vector 0d smart pointers.

You have write 32 line in your program is wrong, rectify that one only.