I am learning c++ and I want to print only alphabet not integer value
Program outputCode:#include <iostream> using namespace std; int main(void) { char alphabet; cout << "Enter an alphabet: "; cin >> alphabet; cout << "You entered alphabet " << alphabet; return 0; }
You entered alphabet b
You entered alphabet 2
How to print only alphabet from a to z not integer value
There's a standard function called isalpha. It can tell you whether a character is alphabetical or not. Use it in combination with an if statement to produce the output you want.
Devoted my life to programming...
If I have to print decimal numbers in the c then I use %d and %c for Character and %s for stringOriginally Posted by GReaper
Is there such an operator in C ++, so that whatever we want to print we can print only that
In C++ you use cout << to print anything. In your case it's like this:
Code:#include <iostream> #include <cctype> using namespace std; int main(void) { char ch; cout << "Enter an alphabet: "; cin >> ch; if (isalpha(ch)) cout << "You entered: " << ch << " = " << static_cast<int>(ch) << "\n"; else cout << "Not a character" << "\n"; return 0; }
Thanks, I am trying to print number from 1 to 10
Program
OutputCode:#include <iostream> using namespace std; int main(void) { int i; for (i=0; i < 11; i++) { cout << "print number: \n " << i; } return 0; }
print number:
0print number:
1print number:
2print number:
3print number:
4print number:
5print number:
6print number:
7print number:
8print number:
9print number:
10
Why number's are printing before message
> Why number's are printing before message
Look at the position
- of the message
- of the newline
- of the variable.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
mmmm
you started with one thing and ended with something else. cool...Code:#include <iostream> using namespace std; int main() { char ch; int i; cout << "Enter a letter " <<endl; cin>>ch; //looking for a number if ( !isalpha(ch) ) cout << " number --> "<<ch<<endl; else cout <<" letter ... "<<ch<<endl; //printing 1 - 10 for (i = 0; i < 10; i++) cout<< i+1 <<endl; return 0; }
Last edited by userxbw; 12-13-2017 at 11:41 AM.
I didn't understand
outputCode:#include <iostream> using namespace std; int main(void) { int i; for (i=0; i < 11; i++) { cout << " print number: " <<i; } return 0; }
print number: 0 print number: 1 print number: 2 print number: 3 print number: 4 print number: 5 print number: 6 print number: 7 print number: 8 print number: 9 print number: 10
OK, so you removed the "\n" from the program code, and now you have no newlines in the output.
What have you learnt?
You need to start thinking along the lines of "If I do this, the following things will happen". Only then will you have any measure of success.
You can't program simply by trial and error.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
I understood what was mistake I have just started writing the program . This was my second program in c++
print number: 0Code:#include <iostream> using namespace std; int main(void) { int i; for (i=0; i < 11; i++) { cout << " print number: " <<i <<"\n"; } return 0; }
print number: 1
print number: 2
print number: 3
print number: 4
print number: 5
print number: 6
print number: 7
print number: 8
print number: 9
print number: 10
Last edited by abhi143; 12-13-2017 at 01:55 PM.
There you go!
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
