hovv do i change players to guess the number and hovv do I make the players guess the numberCode:#include "stdafx.h" #include <iostream> #include <string> #include <ctime> #include <stdlib.h> using namespace std; int main() { cout << "Player 1 = Abel\n"; cout << "Player 2 = Moore\n"; srand(time(NULL)); int random_number; {int random_number = 1 + (rand() % 100); cout << random_number << endl; } int currentPlayerturn; {currentPlayerturn "Player 1"; } system("pause"); return 0; }
Use "cin" to read their input?Originally Posted by sonicflare9
Threaten them? Or,
use "cin" to read their input?
I'd put a your turn user (x) message first then a means to get their guess next then do the rest then print out their results then repeat using a different var for a different user.
you have gone over loops and allowed yourself enough time to work with them to get at least a decent understanding of how they work, other then just know one when you see it?
just a little nudge, not something that is necessarily needed to be used, but just an example of a loop and usages of vars so you won't have to keep writing out the same thing again and again. even though you will still end up doing that anyways if you end up writing the same vars over again and again.
Code://#include "stdafx.h" #include <iostream> #include <string> #include <ctime> #include <stdlib.h> using namespace std; int main() { char what = '\0'; char a[5] = "Abel"; char b[6] = "Moore"; char yourturn[11] = " Your turn"; srand(time(NULL)); cout <<"What is your name?"<<"\n"; cin >> a; cout << "Player 1 is "<< a << "\n"; cout << "Player 2 is "<< b << "\n"; int random_number = (rand() % 100 + 1); while ( what != 'q') { cout << a << yourturn << "\n"; what = 'q'; } return 0; }
Last edited by userxbw; 12-11-2017 at 08:44 PM.
