Thread: help vvith rand and svvitching players

for (int x = 1; x < 100; x++) {
cout << 1 + (rand() % 100) << endl; this gives me a lot of numbers but hovv do i get only one random number

hovv did i random player 1 and player 2 start order to guess a number

cout << "Player 1 = Abel\n";
cout << "Player 2 = Moore\n";

can anyone help me im nevv to c++

The for loop repeats that useful cout statement many times. I vvonder vvhat happens vvhen you remove the looping part and leave the cout statement. :thinking:

vvhere should i put the for loop

Code:

#include "stdafx.h"
#include <iostream>
#include <string>
#include <ctime>
#include <stdlib.h>
using namespace std;
int main()
{
    cout << "Player 1 = Abel\n";
    cout << "Player 2 = Moore\n";

    int random number

    srand(time(0));

    for (int x = 1; x < 100; x++) {
        cout << 1 + (rand() % 100) << endl;
    }
    system("pause");
    return 0;
}

How about putting the loop nowhere?

Code:

 int random_number =  1 + (rand() % 100); 
cout << random_number << endl;

See how that printed one number only.

Now can you code the rest of the guessing game around such a number? (Don't worry if it's actually always the same random number yet, you can seed rand() when the game works)

hovv do i sometimes make player 1 go first and sometimes player 2 go first my teacher said that it involves storing the current player name in a variable

Yes, you would store the current player's name in a variable and then use that variable to make output. No matter whose name you chose to store first in the variable, you have to switch names every turn. It might be easier for player 1 to go first until you get the name switching down. After that, you can make it more complicated by asking the user who should go first.

does it have to do vvith currentPlayerturn