Thread: I'm having trouble with cin.get()

cin.get() is still line buffered. What that basically means is that you will have enough control to type, and then, when you press enter, the entire line will eventually be sent to the program. For example, just try this program.

Code:

#include <iostream>
using namespace std;
int main()
{
   char ch;
   while (cin.get(ch) && ch != '\n')
   {
      cout << ch << '\n';
   }
   cin.ignore(); // just to keep the window open
   return 0;
}

Just run that, enter in a long line and press enter... see how the input is fed to the program.

Also note that cin.ignore() will discard exactly one character typed. The arguments you use will determine how many characters it discards and until some character, passed in, it encounters in the cin stream. If you only use it to keep the window open instead of using cin.get(), you won't really be able to tell, but the difference matters.