Thread: call the function but cannot run

Code:

Code:

void additionmenu()
{
    int choice;
    printf("Please select the level\n");
    printf("1 level 1\n");
    printf("2 level 2\n");
    printf("3 level 3\n");
    scanf("%d", &choice);
    if (choice == 1)
    {
        printf("You have selected level 1\n");
        addEasy();
    }
    else if (choice == 2)
    {
        printf("You have selected level 2\n");
        addMedium();
    }
    else if (choice == 3)
    {
        printf("You have selected level 3\n");
        addDifficult();
    }
    else
    {
        printf("Invalid choice\n");
        menu();
    }
}



here my menu
int main()
{
	int choice = menu();
	printf("You have selected the choice %d\n", choice);


	if (choice == 1)
	{
		printf("You have selected addition\n");
		additionmenu();
	}
	else if (choice == 2)
	{
		printf("You have selected subtraction\n");
		subtractionmenu();
	}
	else if (choice == 3)
	{
		printf("You have selected multiplication\n");
		multiplicationmenu();
	}
	else if (choice == 4)
	{
		printf("You have selected division\n");
		divisionmenu();
	}
	else
	{
		printf("Invalid choice\n");
	}
	system("pause");
}


int menu()
{
	int choice;
	printf("1. Addition\n");
	printf("2. Subtraction\n");
	printf("3. Multiplication\n");
	printf("4. Dividion\n");
	printf("Please choose either 1,2 ,3 or 4 :\n");
	scanf_s("%d", &choice);
	(getchar() != '\n');
	return choice;
}

after invalid i call the menu and menu can display but when i choose i show nothing, cannot continue to do

thank you for your help ....i appreciate that