Thread: call the function but cannot run

  1. #1
    Registered User
    Join Date
    Jul 2017
    Posts
    48

    call the function but cannot run

    Code:
    
    
    Code:
    void additionmenu()
    {
        int choice;
        printf("Please select the level\n");
        printf("1 level 1\n");
        printf("2 level 2\n");
        printf("3 level 3\n");
        scanf("%d", &choice);
        if (choice == 1)
        {
            printf("You have selected level 1\n");
            addEasy();
        }
        else if (choice == 2)
        {
            printf("You have selected level 2\n");
            addMedium();
        }
        else if (choice == 3)
        {
            printf("You have selected level 3\n");
            addDifficult();
        }
        else
        {
            printf("Invalid choice\n");
            menu();
        }
    }
    
    
    
    here my menu
    int main()
    {
    	int choice = menu();
    	printf("You have selected the choice %d\n", choice);
    
    
    	if (choice == 1)
    	{
    		printf("You have selected addition\n");
    		additionmenu();
    	}
    	else if (choice == 2)
    	{
    		printf("You have selected subtraction\n");
    		subtractionmenu();
    	}
    	else if (choice == 3)
    	{
    		printf("You have selected multiplication\n");
    		multiplicationmenu();
    	}
    	else if (choice == 4)
    	{
    		printf("You have selected division\n");
    		divisionmenu();
    	}
    	else
    	{
    		printf("Invalid choice\n");
    	}
    	system("pause");
    }
    
    
    int menu()
    {
    	int choice;
    	printf("1. Addition\n");
    	printf("2. Subtraction\n");
    	printf("3. Multiplication\n");
    	printf("4. Dividion\n");
    	printf("Please choose either 1,2 ,3 or 4 :\n");
    	scanf_s("%d", &choice);
    	(getchar() != '\n');
    	return choice;
    }

    after invalid i call the menu and menu can display but when i choose i show nothing, cannot continue to do

  2. #2
    and the hat of int overfl Salem's Avatar
    Join Date
    Aug 2001
    Location
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    Posts
    39,653
    You need to have a loop somewhere, if you want the option of going round again.
    Code:
    int main ( ) {
      int choice;
      while ( (choice=menu()) != 5 ) {  // Add "5. Quit" to the menu() function
        printf("You have selected the choice %d\n", choice);
        // etc
      }
    }
    > printf("Invalid choice\n");
    > menu();
    No, you return to main() and let it call menu() again.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  3. #3
    Registered User
    Join Date
    Jul 2017
    Posts
    48
    thank you for your help ....i appreciate that

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