Thread: HELP! (strings)

Originally posted by mana
i been asked to write a program that accepts a word into a string variable, and it has to display the number of the vowels and the number of consonants of the word.
would you help me solve this?
i don't know how to get the words separated (vowels from consontats)

#include <iostream.h>

int main ()
{
char word, vowel, consonat;

cout<<"Please enter a word"<<endl;
cin>>word

First and foremost, you can't use a character to hold a word. You need to have an array of characters (or a character pointer to an allocated amount of memory). You seem pretty new so I'm just going to suggest that you look up character pointers (char *) and then look at the string object.

Good luck.

// This code runs perfect
// HAVE FUN!! [email protected]

#include <iostream.h>

int main ()
{
char word [50];
int vowel=0, consonat=0;
int count = 0;
cout<<"Please enter a word: ";
cin>>word;

while(word[count] != '\0')
{
if((word[count] == 'a')||(word[count] == 'e')||
(word[count] == 'i')||(word[count] == 'o')||
(word[count] == 'u'))
{
vowel++;
}
else
{
consonat++;
}
count++;
}
cout<<"Number of the vowels "<<vowel<<endl;
cout<<"Number of the consonants "<<consonat<<endl;
}

>// This code runs perfect

Unless the CAPS LOCK is on.

Here's a simple program to do what you ask. Remember this will only take a word not a string, so if you plan on having spaces this will NOT work, but in your original post you said "word".

Code:

#include <stdio.h>
#include <ctype.h>
#include <fstream.h>

int main( void )
{
  ofstream fout("MyProjects\\info.dat");
  char Array[255];
  int nVowels = 0, nCons = 0;

  cout << "Enter a word: ";
  cin >> Array;

  for( register int i = 0; i < strlen( Array ); i++ )
  {
       // Convert letter to lower-case
       Array[i] = tolower( Array[i] );

       // Switch on the character to determine type
       switch( Array[i] )
       {
               case 'a':
                    nVowels++;
                    break;
               case 'e':
                    nVowels++;
                    break;
               case 'i':
                    nVowels++;
                    break;
               case 'o':
                    nVowels++;
                    break;
               case 'u':
                    nVowels++;
                    break;
               default:
                    nCons++;
                    break;
       }
  }

  // Output data to a file
  fout << "Word is " << Array << endl;
  fout << "Number of Vowels - " << nVowels << endl;
  fout << "Number of Consonants - " << nCons << endl;
  fout << "Total letters in word - " << (nCons + nVowels) << endl;

  // Close the file after writing to it
  fout.close();

  return( 0 );
}

Originally posted by Hammer
But what happens when you enter a word with non-alpha characters in it.... the counts are lying! for example:

That's a very good point. I wrote that program in about 3 minutes without thinking much of user-error. Simply add the following code to execute first in the for loop.

Code:

if( !isalpha( Array[i] ))
{
     continue;
}