Fill Positions of one Array into another Array
Okay I have two arrays
face *A[21];
face *B[21];
i need to put positions 0-3-6-9-12-15-18 of A into 0 through 6 of B
1-4-7-10-13-14-19 of A into 7 through 13 of B and 2-5-8-11-14-21 of A into 14-20 of B.
I can't figure out how to do this, any help you can offer will be greatly appreciated.
Use a temp array to swap between. Swap all of array A into the temp, then copy the section of array B needed into array A. Finally copy the section from array A (stored in the temp array) into array B.
do your own homework assignment u dink...
if you ever used arrays before you would know how to do this without a problem.
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Originally posted by Liam Battle
do your own homework assignment u dink...
if you ever used arrays before you would know how to do this without a problem.
Come on man, although you might be right, this is not the way to reply to this man, this is not contributing to the thread....plus it's not nice
There are some real morons in this world please do not become one of them, do not become a victim of moronitis. PROGRAMMING IS THE FUTURE...THE FUTURE IS NOW!!!!!!!!!
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...gimme a break! the guy didn't even post any code...Come on man, although you might be right, this is not the way to reply to this man, this is not contributing to the thread....plus it's not nice
Code:#include <cmath> #include <complex> bool euler_flip(bool value) { return std::pow ( std::complex<float>(std::exp(1.0)), std::complex<float>(0, 1) * std::complex<float>(std::atan(1.0) *(1 << (value + 2))) ).real() < 0; }
I dont think that any source code was needed for the type of description that he gave. Also, what is the purpose of a message board if people dont co-operate and respect eachother. Its to exchange knowlege and help eachother out. Beginners may struggle with some concepts, just as everyone does as they learn.
i was just wondering if anyone had anyway to do it in a for loop instead of manually swapping all the values 1 by 1, thanks to most who replied..
Maybe something like this??
Code:for(int x=0;x<22;x++) { if(x%3==0) { B[x/3]=A[x]; B[x/3+7]=A[x+1]; B[x/3+14]=A[x+2]; } }
