Thread: Can not read the file, I can not quite help!

Good time day!!
I welcome all to a nice wonderful forum.

Code:

 int main(int argc, const char **argv, const char **envp)
{


        spilna_pamyat s, *Ps=&s;


        ZeroMemory(&s, sizeof(s));








char* mas =new char[];
//В цей масив будемо зберігати файл








  ifstream fs8("test_file_path.txt");
    if (!fs8.is_open()) {
        cout << "Не вдалося відкрити" << "test_file_path.txt" << endl;
        return 0;
    }


  ifstream dzherelo ( "test_file_path.txt", ios::in | ios::binary);
  ofstream priymach ( "produkt.txt", ios::app | ios::binary);


  vstavlyannya(22, 666.66, Sui, priymach);

How to read the file into an array of unknown size, eg
997,7KBu a prototype and later possibly more.
You can expect to hihobayta likely. The key word is unknown.
And under the same file, such test_file_path.txt - it probably bit data items, possibly large amounts
text encoding UTP-8.


in prototype and in the future possibly more.
You can big large, hyhabaytiv likely.




There is a stream, such as a so


[code] ifstream dzherelo ( "test_file_path.txt", ios :: in | ios :: binary);
ofstream priymach ( "produkt.txt", ios :: app | ios :: binary);
[/code]


How do I cope with it? More precisely, I had a whole head burned, and I do not understand razumiyu what to do with the flow dzherelo at all, I just can not imagine.
First, make it somehow to the array? Clearly dynamically allocated array?
Anyway, I know how long I order it?


I really want an explanation, but rather all sorts of code samples, links can even link to a professional code.


I beg you, help please! Waiting for answers!