Thread: Why my code will cout the string twice?

This is a password check code.When I enter the right password,it outputs "access allowed!access allowed!"
When password is wrong,it outputs "try again!try again!".
Why is this happened? Thanks for any help!

Here is my code:

Code:

#include <iostream>
#include <string>
using namespace std;
int check(string x)
{
    if(x=="pppp")
         {
             cout<<"access allowed!";
             return 3;
         }
         else
         {
             cout<<"try again!";
             return 1;
         }


}


int main()
{
    int i;
    string pass;
    do
    {
         cout<<"enter a password:";
         cin>>pass;
         check(pass);
         i=check(pass);
    }while(i==1);


}