Hi,
I want to open an application A from another application B. By opening it, I don't want to open it within B. I found many ways to call an application from within another. However, what I want to do is open the other one(A) simultaeneously. How can I achieve this? fork() and exec() seem to open A within B. I am developing a code for Linux and Mac. Advice would be appreciated.Thanks.
What do you mean "within B?" fork() creates a new process that is a clone of the current one, and exec() then replaces that process with the new program that you specify.
What can this strange device be?
When I touch it, it gives forth a sound
It's got wires that vibrate and give music
What can this thing be that I found?
No No, fork + exec() are opening the application within the service's terminal window. I want both of them to run concurrently without interrupting each other. The application should open in a new terminal window.
fork() and exec() know nothing about "terminal windows." They are system calls, and have no knowledge of your windowing environment, or even the terminal. You can allocate a new virtual terminal, but I don't know how you would attach it to a new "terminal window."
What can this strange device be?
When I touch it, it gives forth a sound
It's got wires that vibrate and give music
What can this thing be that I found?
Instead of executing the program directly, use xterm to execute it and it will pop a new window:Originally Posted by Elkvis
Call that with exec() instead of calling the program directly.Code:xterm -e <program> <args...>
Code://try //{ if (a) do { f( b); } while(1); else do { f(!b); } while(1); //}
O_oCall that with exec() instead of calling the program directly.
But inspect the environment ($TERM) first so that you have a change of using the preferred emulator.
Soma
“Salem Was Wrong!” -- Pedant Necromancer
“Four isn't random!” -- Gibbering Mouther
