using array to enter number of users and their data

[alimr78]

Hi,
I have a small program to calculate the value of salary. I want to user to be able to enter more than one user using array and finally calculates the average salary of all users.
Here is the code

#include <iostream>#include <conio.h> 
using namespace std;


int main() {
	const int months=3;
	double net_pay;
	string EmpName;
	string date_of_birth;
	int hours, dependents;


	cout<<"Please enter your name: " ;
	cin>>EmpName;


	cout<<"enter your birth date: ";
	cin>>date_of_birth;


	


	do {
		cout<<"How many hours you work everyday: (Please                   choose 8, 10 or 12 only): ";
		cin>>hours;
	} while(hours != 8 && hours != 10 && hours != 12);
	
	cout<< "How many children you have? ";
	cin>>dependents;


	if (0<dependents<10) {
		if(hours==8) {
			net_pay= months*300; 
		} else if (hours==10) {
			net_pay= (months*300)+(5*dependents);
		} else if (hours==12) {
			net_pay= (months*400)+(10*dependents);
		}


		cout<<" Hello "<<EmpName<<"...  Your Salary is "<<net_pay<<endl ;
	} else {
		cout<<" Please choose correct values"<<endl ;
	}


	 getch(); 
          
	return 0;


}

Thanks in advanced

[grumpy]

What have you tried?

Seriously, there is no array in that code at all. (except for the minor philosophical aside that a std::string might notionally represent its data using an array).

Giving code for something, and saying you want to use an array to make it work for multiple somethings, does not cut it for demonstrating at least some effort to solve your own problem (do your own homework).

[Elysia]

>>if (0<dependents<10)
Note that C++ does not understand mathematical range notation. This is equal to:

if ((0 < dependents) < 10)
which is equal to
if ((true or false) < 10)
which is equal to
if ((1 or 0) < 10)
which is always equal to true.

You have to separate them:
if (dependents > 0 && dependents < 10)