Thread: I created my own print function but it isn't as good as the C function

>So whats wrong with my print function?

It uses other peoples print functions. Apart from that it should probably look something like -

Code:

#include <iostream> 
#include <string> 

using namespace std;

void myprintf(string outprint, int integer, char character, float floatpoint); 

int main() 
{ 
myprintf("Hello World!!\n", 8, '\n', 9.70); 
cin.get(); 
return 0;
} 

void myprintf(string outprint, int integer, char character, float floatpoint) 
{ 
outprint=""; 
cout << outprint; 
cout << integer; 
cout << character; 
cout << floatpoint; 
}

Not sure why you're erasing outprint before outputting it though.

Wow great.. I though he had created his own header and defined printf..

if you use the parameters
(const char *fmt, ...)
doesn't that create the equivalent of printf?

eh... well, this is worthless... the purpose of there already being a printf is so that you don'thave to write your own.

...i'd suggest doing something more productif, aktif, rejuvanatif.
(doubleantif.)

as long as you're doing that, why not just output through the real printf function?
or you can output directly to memory

well, anyway, if i was doing what you are adoing, GB, i would go as low level as possible with it instead of using a function on the same or higher level.

I agree with Prelude and Aran Elus. Writing the standard library functions are fun and can be worth learning. However, if you are going to do so, try and do it with functions that are on a different level. Like this:

Code:

int myPrint(const char *string, int size)
{
   for(int i = 0; i < size; i++, string++)
      putchar(*string);

   putchar('\n');

   return i;
}

Instead of using cout << or printf(), I used the old C putchar(). Try something like that.

Have fun

You dont learn anything by making a function which uses cout only.
If you do it without any of the other output functions then thats another thing =)