Thread: bash to cpp

Hi.

I'm new in C++ and sure - I'm learning it.

But - just interesting - how next bash function can't looks like in C++?

This code used to check array of system global variables:

Code:

#!/usr/bin/env bash

# defining and fill array
variables=( [1]=$sysvar1 
            [2]=$sysvar2 
            [3]=$sysvar3 
            [4]=$sysvar3 
          )

# function 
checkvars () {

local var

# run loop for list of arguments one-by-one
for var in "$@"
do
  # test - if $var not empty will print "Var exist"; else - "Empty var"
  [[ "$var" ]] && echo "Var exist: $var;" \
    || echo "Empty var!"
done
}

# start function with array as argument
checkvars "${variables[@]}"

It's simple enough and I hope C++ code will not be too complicated for me to understand it :-)

Thanks.

P.S. Goal of post - not really made some job for me - but show an example of some C++ code, which I'll can sort out and compare with bash code.
Some explanations will be nice.

Thanks for tip, @laserlight .

Yes, I'm using Linux.

About: and use std::getenv rather than just getenv

Code:

$ cppman -f std::getenv
error: std::getenv: nothing appropriate.
$ cppman -f getenv
getenv
fegetenv

Do you mean 'getenv'?

From manual - it's look like correct:

Code:

NAME
       getenv - Get environment string


TYPE
       function


SYNOPSIS
       #include <cstdlib>


       char* getenv (const char* name);

Usually - `cppman` can recognize `std` namespace:

Code:

$ cppman -f std::cin
std::cin

It takes data from cplusplus.com - The C++ Resources Network.

Anyway - thanks, now I have one way for searching :-)