Implement a simple “password” system that takes a password in the form of a number. M

**Ezio Altair** · 06-29-2014

Hi there I'm having a problem with my code:
Question: Implement a simple “password” system that takes a password in the form of a number. Make it so that either of two numbers is valid, but use only one if statement to do the check.

Code:

#include <iostream>



using namespace std;




int main ()
{
int password;


cout << "Enter password\n";
cin >> password;
if ( password == "123" || "456" ) // line 13
{
    cout << "access granted\n";
}
else
{
    cout << "Incorrect password\n";
}
}

Error

**grumpy** · 06-29-2014

The reason for the compiler complaints is that "123" is a string literal, not an integral value.

Although you didn't ask about it, I'll point out another major flaw in your code.

Although the compiler didn't complain about it the construct

Code:

  if ( password == some_constant || some_other_constant)

is not a test of whether password is equal to one of some_constant or some_other_constant. It is actually equivalent to

Code:

  if ( (password == some_constant) || (some_other_constant != 0))

If you want to test if password is equal to some_constant or equal to some_other_constant, you need to do this;

Code:

  if ( (password == some_constant) || (password == some_other_constant))

I've left brackets around the two comparisons for clarity - they are not actually required since == (compare for equality) has higher precedence than || (logical or).

Thread: Implement a simple “password” system that takes a password in the form of a number. M

Thread Tools

Search Thread

Display

Implement a simple “password” system that takes a password in the form of a number. M

Similar Threads

Simple password system

To enter password without displaying it in a password checking program

system() clear password (XP)

How can I display the system password

Password form in C program