Thread: template functions as member functions

I want to have a template function that is a member of a class. Is this possible? This code snippet is how I would think the syntax would go, although it doesn't compile. How would I achieve the same effect?

Code:

class myclass
    {
    public:
	int member ;
    } ;

template <typename T> void myclass::func( T& arg )
    {
    T = member ;
    }

int main()
    {
    myclass instance ;
    instance.member = 0 ;

    int copy ;
    instance.func<int>(copy) ;

    double copy2 ;
    instance.func<double>(copy2) ;
    }

I think you might have to template your class as well. But what's wrong with compiling the code you wrote yourself?

Thanks, laserlight. Id did have a stupid type on there. What I originally couldn't get working was when the class is itself a template:

Code:

template <int N>
class myclass
    {
    public:
        int member ;
        template <typename T> void func( T& arg ) ;
    } ;

template <int N> template <typename T>
void myclass<N>::func( T& arg )
    {
    arg = member ;
    }

Works now. I was using template<int I,typename T>, which doesn't work.