Thread: Finishing Off My Program

You need to indent your code properly. For example:

Code:

#include <stdio.h>

int main()
{
    int data[10], n, i, j, hold, k;

    printf("Enter number of Expected Times: ");
    scanf("%d", &n);

    printf("Enter Expected Times: ");
    for (i = 0; i <= n - 1; ++i)
    {
        scanf("%d", &data[i]);
    }

    for (i = 1; i <= n - 1; ++i)
    {
        for (j = 0; j < i; ++j)
            if (data[j] < data[i])
                printf("The Expected Times Are: ");

        scanf(-----This is where I am stuck...

        {
            hold = data[i];
            k = i;

            while (k != j)
            {
                data[k] = data[k - 1];
                --k;
            }
            data[j] = hold;
        }
    }

    printf("In descending Order: ");
    for (i = 0; i <= n - 1; ++i)
    {
        printf("%d    ", data[i]);
    }

    return 0;
}

Originally Posted by Steveqb14

I started from scratch and I came up with the program I needed, my only problem is that I want to output each array entered before I put them in descending order. Right now the user enters each term, then it outputs them in descending order. I want the program to output each term entered and then put them in descending order.

I think that what you mean is that at every step of the sorting algorithm, you want to print the array as it is. Is that correct? If so, then there's no sense having that scanf in that part. Rather, you should print similiar to how you printed the array at the end.

By the way, instead of writing i <= n - 1, write i < n.

Right. My guess is that you're confused here because in your loop to print the numbers at the end, you use i as the loop index. i has already been used as the loop index in the loop to perform the sorting.

One simple way out is to write a function to print the array. Do you know how to write a function other than the main function?

Right. Then, either learn how to write a function, or write a similiar loop but with a different (presumably new) loop index.