Thread: derived destructor problem in inheritance

Hi;
I have a short question about pointer and derived inheritance
I have a class Base and a class Derived; they have constructor and destructor.

in main I create it
Base *p=new Derived();
but the output is
Base Constructor
Derived Constructor
Base Destructor
.......................... where is Derived Destructor ? why It is not called ?

Code:

#include<iostream>

using namespace std;

class Base
{
public:
    Base()  {cout<<"Base Constructor"<<endl;}
    ~Base() {cout<<"Base Destructor"<<endl;}
};

class Derived: public Base
{
    public:
    Derived() {cout<<"Derived Constructor"<<endl;}
    ~Derived() {cout<<"Derived Destructor"<<endl;}
};

int main()
{
    Base *p=new Derived();
    delete p;

    return 0;
}

watch this:
Buckys C++ Programming Tutorials - 52 - Inheritance - YouTube

This breaks down this question for you.

thank you I got it =)
if without virtual destructor

Code:

#include<iostream>

using namespace std;

class Base
{
public:
    Base()  {cout<<"Base Constructor"<<endl;}
    ~Base() {cout<<"Base Destructor"<<endl;}
};

class Derived: public Base
{
    public:
    Derived() {cout<<"Derived Constructor"<<endl;}
    ~Derived() {cout<<"Derived Destructor"<<endl;}
};

int main()
{
    Base *p=new Derived();
    delete p;

    return 0;
}

OUTPUT
Base Constructor
Derived Constructor
Base Destructor


if with virtual destructor

Code:

#include<iostream>

using namespace std;

class Base
{
public:
    Base()  {cout<<"Base Constructor"<<endl;}
   virtual ~Base() {cout<<"Base Destructor"<<endl;}
};

class Derived: public Base
{
    public:
    Derived() {cout<<"Derived Constructor"<<endl;}
    ~Derived() {cout<<"Derived Destructor"<<endl;}
};

int main()
{
    Base *p=new Derived();
    delete p;

    return 0;
}

OUTPUT
Base Constructor
Derived Constructor
Derived Destructor
Base Destructor