This is my code:
[tag]Code:#include <iostream> #include <string> #include <cstring> #include <vector> using namespace std; void v_abs( vector <int> &x, double p[] ) { int i=0; while( p[i] < x.size () ) { if ( p[i] < 0 ) { p[i] *= -1 ; i ++; } } } int main(){ cout<<v_abs<<endl; system("pause"); return 0; } [/tag]
idk, I can't execute correctly.
1. Why does your v_abs function take both a vector and an array of doubles?
2. Why does your function not use the vector?
3. Why does your function not use abs?
4. Why do you not pass anything to your function?
Originally Posted by tabstop
It sure not take both a vector and an array of doubles?
What is the array for? Make the function iterate over the vector, read in each value, calculate the absolute value, write the result to the vector, rinse and repeat. No need for an array.
How I need a drink, alcoholic in nature, after the heavy lectures involving quantum mechanics.
cout<<v_abs<<endl;
What does that even do? I can't even follow this code. std::cout a void return?
I think you may have cut a little too much code out of what you are doing here.
NOTE: if you use abs include stdlib or it won't workCode:#include <vector> #include <iostream> int main() { std::vector <double> numbers; numbers.push_back(-1.0); numbers.push_back(3.0); numbers.push_back(-5.0); numbers.push_back(7.0); numbers.push_back(-9.0); numbers.push_back(11.0); for(unsigned int i = 0; i < numbers.size(); i++) { if(numbers[i] < 0)numbers[i] *= -1; //make positive. _OR_ use numbers[i] = abs(numbers[i]); std::cout<<numbers[i]<<std::endl; } //vector is now absolute valued. return 0; }
Last edited by ~Kyo~; 12-10-2013 at 02:34 AM. Reason: added Note
