the post increment operater will be executed first -> first the pointer is incremented pointing to the next int in memory and that is dereferencedCode:for(int i =0; i<10; i++) { cout <<a<<"\n"; *b++; //shouldn't this assigned a new value to a?? }
you want (*b)++
Kurt
That's not exactly correct. The expression b++ has the effect of incrementing b, and a result equal to the original value of b. It is then the original value of b that is dereferenced.Originally Posted by ZuK
First time through the loop *b++ produces a result equal to a, and increments b. The other times through the loop, however, start with b pointing to a non-existant variable (or location in memory). So dereferencing produces undefined behaviour (and the increment causes b to walk through memory that, as far as the program is concerned, does not exist).
