Need ur lil time......2 wk in progrmming!
( C++ )
Should print multiple of 2 infinite
Code:#include<iostream.h> #include<conio.h> void main( ) { clrscr( ); int number=2; //declaration while( number>=2 ) { cout <<number <<" \n "; //will print multiples of 2 in in columns number *=2; } getch(); }
unfortunately this will be terminated by printing 32768 value
need ur help/suggestions .
What you want cannot be done. At some point, you will have to stop printing multiples of two. In your case, it stopped because number was doubled beyond the maximum value for int, and presumably this arithmetic overflow resulted in number having a negative value, thus terminating the loop.
Even if you change number from being an int to be say, an arbitrary precision integer type, you still cannot print multiples of two indefinitely: there is a limit to your computer's memory and such, and even if there wasn't, I doubt that you are immortal.
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
Hold on now, let's not be too presumptuous...
Code:#include <cmath> #include <complex> bool euler_flip(bool value) { return std::pow ( std::complex<float>(std::exp(1.0)), std::complex<float>(0, 1) * std::complex<float>(std::atan(1.0) *(1 << (value + 2))) ).real() < 0; }
[assumption]Plz drop that TurboCrap you're using for a compiler that's younger than me.[/assumption]
Devoted my life to programming...
How old is Turbo Crap?
Too old
Depending on version, release dates start at around 1987.
Jim
The version i was using is 3.8.0.1....
Assumption wrong, still valid though!
Devoted my life to programming...
