How is this happening?(linked lists)

[Konstantinos]

Hello,i am getting something strange and unfortunetely i dont understand it.

#include "LinkedList.h"

void concatenate(LinkedList<string>& object1,LinkedList<string>& object2){
 if(object1.head==NULL){
    object1.head=object2.head;
 }

}



int main(){
    
    LinkedList<string> LinkedList1;
    LinkedList<string> LinkedList2;
    LinkedList2.AddNode("anna"); 
    LinkedList2.AddNode("montanna");
    LinkedList2.AddNode("annamontanna");
    
    concatenate(LinkedList1,LinkedList2);
    LinkedList1.DisplayList();
    
    keep_window_open();
    
}

void DisplayList(){
      curr=head;
      while (curr!=NULL){
      cout<<curr->data;
      curr=curr->next;
      }
    }

How come object1.head=object2.head; copy the the entire object2 list to object1 list by just copying the head of it?

[Elysia]

Because it's a pointer. You should review how they work.
Your concatenate function is wrong, though. You should insert the second list at the end of the first list (or vice versa).

[Konstantinos]

Because it's a pointer. You should review how they work.
Your concatenate function is wrong, though. You should insert the second list at the end of the first list (or vice versa).

Thanks.This was just the case where the first list was empty,i am about to implement the second case now.