Hi,
I'm trying to use cin to get input in a specific format.
Say I have this string as an input: "+ Baraq 112540783 AB1234"
I want my variables to look like that:
name = "Baraq"
id = 112540783
book = "AB1234"
now I am sure there is something with providing the format of the input " %s %s %s" or something like that, just not sure how to use it.
I have tried to find an example but couldn't get how to use it.
Thank you (:
gavra.
IF you know you have an input that looks like the above, you can take advantage of the fact that std::cout skips whitespace, so:
std::string Plus; // For the "+" char.
std::string Name, Id, Book;
std::cin >> Plus >> Name >> Id >> Book;
Of course, Id could be an int, too.
If your input is NOT as the above, then this may produce unpredictable results. Just so you know.
Originally Posted by Adak
Thank you, that's what I was looking for, But since I have two format variations I can't use it like that. Is there a way to read the whole line(to a string) and then split to my variables with the format I choose?
First format: "+ name id book"
Second format: "+ name id"
Thanks again.
gavra.
Yes, you could use std::getline.
std::string Line;
std::getline(std::cin, Line);
Now you have the entire line in your variable which you can parse.
For example, you can do:
std::stringstream sstr(Line);
sstr >> Plus >> Name >> Id;
if (sstr >> Book)
/* Whatever */ ; // There was a book in there, too. Do something with it.
Extraction will fail if there is nothing left to extract. Stringstreams also skips whitespace.
Last edited by Elysia; 04-28-2013 at 01:31 PM. Reason: Syntax error
ok, great. Thank you!
gavra.
This works too:
Code:string name, book, id, plus; cin >> plus >> name >> id; if ( cin >> book ) ... else cin.clear();
