Converting 1d vector into 2d vector

[Khabz]

#include <iostream>
#include <vector>

int main()
{
      std::vector<std::vector<double> > DV;   //2d vector
      std::vector<double>temp(8,0.0);  //1d vector
        
      temp[0] = 1;
      temp[1] = 2;
      temp[2] = 3;
      temp[3] = 4;
      temp[4] = 5;
      temp[5] = 6;
      temp[6] = 7;
      temp[7] = 8;

      DV.resize(3, temp); 

      for (int i = 0; i < DV.size(); i++)
      {
          for (int j = 0; j < DV.size(); j++)
          {
            std::cout << DV[i][j];
          }
      }
    std::cin.get();
}

The convertion actually works but it does not give the expected the result. The output should be:

1 2 3
4 5 6
7 8

and it outputs:

123123123

Can anyone help me? Thanks.

[ZuK]

DV.resize(3, temp);

This will initialize the 2d vector with 3 copys of temp
try

      for (int i = 0; i < DV.size(); i++)
      {
          for (int j = 0; j < DV[i].size(); j++)
          {
            std::cout << DV[i][j] << " ";
          }
          std::cout << std::endl;
      }

Kurt

[Khabz]

It still displays a full row like this:
1 2 3 4 5 6 7 8

[ZuK]

It still displays a full row like this:
1 2 3 4 5 6 7 8

I know that this will display 3 times the above line. My code was just to make clear what DV actually contains. It is your job to extract the right values.
Kurt

[Khabz]

Before I posted my reply I changed from >DV.resize(3, temp); to >DV.resize(1, temp);

Ok so if DV contains what I posted above, shouldn't it print out:

1 2 3
4 5 6
7 8

instead of 1 2 3 4 5 7 8 ?


Edited: Oh, I got it. So the vector contains the numbers from 1->8 from DV[0][0->8] instead of DV[0][0->2], DV[1][0->2] and DV[2][0->2]

[ZuK]

Why do you think it would insert line breaks after 3 elements ?
Kurt