Thread: Simple 2D array problem...In a Hurry!

What exactly is wrong with this section of code. All I want to do is read in numbers into a 4X4 array and then output them to the screen in a 4X4 pattern. Please let me know what I am doing wrong ASAP. Thanks!

P.S. Is there a way to enter the numbers by row (separated by spaces) instead of each individual like I am doing? If so, how? Thanks again!


#include <iostream.h>
#include <iomanip.h>

int main()
{
int grid[4][4]={0};
bool magic = true;

int row, col;
for(row=0; row<4; row++)
{
for(col=0; col<4; col++)
{
cout << "Please enter the value for row " << row << ", col " << col << ": ";
cin >> grid[row][col];
}
}



for(row=0; row<4; row++)
{
for(col=0; col<4; col++);
{
cout << grid[row][col];
}
cout << endl;
}
return 0;
}

Should be like this....

Code:

#include <iostream.h> 
#include <iomanip.h> 

int main() 
{ 
int grid[4][4]={0}; 
bool magic = true; 

int row, col; 
for(row=0; row<4; row++) 
{ 
 for(col=0; col<4; col++) 
 { 
  cout << "Please enter the value for row " << row << ", col " << col << ": ";  
  cin >> grid[row][col]; 
 } 
} 



 for(row=0; row<4; row++) 
 { 
  for(col=0; col<4; col++)   // THIS LINE! NO ;
  { 
   cout << grid[row][col]; 
  } 
  cout << endl; 
 } 
return 0; 
}

Semicolons after for loops declarations are no-no's.

Gr3g: Fills the entire array with 0.

for (i = 0; i < 10; i++);
{
stuff;
}

The for loop ends on the same line it is created, then the brackets are just used to specify code blocks.

{
stuff;
}

So do I
Habit I guess...

Oh, and also, you can't refill your arrays using the above method... you must loop through like you stated.