1. ## question in cin(homework)

ok, heres my main

Code:
```class BigNum{
public:
char input[1000];
BigNum();
BigNum(char* );
char* convert(char *);
int counter;
};

BigNum output;    char num1[1000];
char num2[1000];
char *numm1;

cout << "Enter first input"<< endl;
cin >> num1;
cout << endl;
BigNum input1(num1);
numm1 = input1.convert(num1);
strcpy(num1, numm1);

cout << "Enter second input"<< endl;
cin >> num2;
BigNum input2(num2);
numm1 = input2.convert(num2);
strcpy(num2, numm1);

return 0;
}

BigNum::BigNum(char* input){
strcpy(this->input, input);
}

BigNum::BigNum(){
strcpy(input, "\0");
counter = 0;
}

char* BigNum::convert(char* input){
int temp, temp2, temp3;

for(temp = 0;input[temp] != '\0';temp++);
temp = 1000 - temp;
for(temp2 = 0;input[temp2] != '\0';temp2++, temp++){
input[temp] = input[temp2];
}
temp2 = 1000 - temp2;
for(temp3 = 0;temp3 < temp2;temp3++){
input[temp3] = '0';
}
input[1000] = '\0';
return input;
}```
the convert function simply moves the numbers in the string to the end of the string so it looks like from "123\0" into "00000123\0" where \0 is the end of string.

my problem is during my second cin for the second input. when i display my first input right after the cin of the second input, the second input gets connected/combined with my first input. its like: if my first input is 123. my first input, after going through the convert function, would look like this 0000123. then i would put my second input, which would be 321. if i display my first input right after the cin of the second one, it would look like this 0000123321. why?

2. A couple of notes:
- Why are you using char arrays instead of std::string, or even a vector of char?
- There seems to missing a piece between the class definition and the code (in main, I believe?).
- Please adhere to this: SourceForge.net: Do not remove parameter names - cpwiki
- Do not make everything in a class public. Only the interface that the outside should use to use the class.
- You realize that your convert function actually modifies whatever you input? So after you do input1.convert(num1), num1 already contains the "converted" string. So your strcpy is useless. This is really dangerous, btw.