1. ## Formula Error

So i am not getting the formula for the last one I'm not sure why it is not coming out. And also for the Fahrenheit my value keeps equaling to 0 I am not sure why.

Code:
```//study iomanip to depth for this project
//to define a constant use #define PI 3.14159

#include "stdafx.h"
#include <iostream>
#include <iomanip>

#define PI 3.14159
#define g  9.81
using namespace std;

int main()
{

double Volume,SurfaceArea,Circumference,Area,Sum, SideA;
int F,K,C; // temperatures
double Number, a, l;
double P,V,R,T

SideA = 15; // This is the base of the triangle
Height = 3;
Area = 1 * SideA * Height / 2;
cout << "\n\t\tThe area of this beautiful triangle = "
<< Area;

//Volume of Sphere
Height =  3;
cout << "\n\t\t The volume of this cone = " << Volume;

//The Sum
Number = 4;
a = 1;
l = 7;

Sum = Number/2 * (a+l);
cout<<"\n\n\n The Sum of this sum = " << Sum;

// I don't know
SlantHeight = 4;

Area = PI * Radius * SlantHeight * 1/2;
cout<<"\n\n\n The Area of this = " << Area;

//Celcius
C = 100;
cout << "\n\t\tThe value of 5 / 9 * (F - 32) = "
<< 5/9* (F - 32) << " Farenheit";

//Farenheit
F = 150;
cout <<"\n\t\tThe value of 9 / 5 * C + 32 = "
<< 9/5 * C + 32 <<" Celcius ";

//  Last Formula
P = 3;
V = 6;
R = 2;
T = 7;

Number = P*V/T*R;

cout<<"\n\n\t The value of P * V/ T* R = " << Value;

cout << "\n\n\n";
return 0;
}```

2. Integer arithmetic. Let's look at the expression
Code:
`   cout << 5/9 * (F - 32);`
In your code, F is of type int, although that doesn't affect how 5/9 is computed.

So what happens?

5 is interpreted by the compiler as being a literal of type int. So is 9. Computing 5/9 therefore involves integer arithmetic - it produces a result of type int with rounding toward zero (since both 9 and 5 are positive). Hence 5/9 is computed as zero. Since F is an int, F - 32 is also computed, with type int. Then the two intermediate results (5/9 which has value zero, and F - 32) are multiplied, giving output of zero.

The fact that you think 5/9 is a fraction does not mean the compiler does.

To get the result you expect, you need to force the division 5/9 to be done as a floating point operation. The way that happens is to convert either the 5 or the 9 (or both) to be floating point. In the following code, each line has the same result.
Code:
```   cout << 5.0/9 * (F - 32);        /*   5.0 is of type double, so 9 is converted to double before doing division. */

cout << 5/9.0 * (F - 32);        /*   9.0 is of type double, so 5 is converted to double before doing division. */

cout << 5.0/9.0 * (F - 32);        /*   5.0 and 9.0 are both of type double, so dividing them produces a result of type double.  */

cout << (double)5/9 * (F - 32);   /*  This forces the compiler to convert 5 to double.   9 is therefore converted to double before doing the division, and the result is of type double. */

cout << 5/(double)9 * (F - 32);   /*  This forces the compiler to convert 9 to double.   5 is therefore converted to double before doing the division, and the result is of type double. */

cout << (double)5/(double)9 * (F - 32);   /*  This forces the compiler to convert both 5 and 9 to double.  The result of division is of type double. */```
Note that, in every case above, F-32 is computed as an int, which is then converted to double (since 5/9 has been computed as a double) before doing the multiplication.

3. Also posted here.

Jim

4. It's a little late to reply but I sorted it thanks guys! Changed the 5/9 to 5.0/9.0 and it worked