Thread: Static vector of shared_ptr

That doesn't make sense. If it's static, it exists once per class (once per T here because Grid<int> is another class than Grid<double>) and you shouldn't allocate memory once per instance of a class.

Are you sure that ALL grids of type int should share the same cell_grid?

Originally Posted by nvoigt

That doesn't make sense. If it's static, it exists once per class (once per T here because Grid<int> is another class than Grid<double>) and you shouldn't allocate memory once per instance of a class.

Are you sure that ALL grids of type int should share the same cell_grid?

All Grid<Derived> should share the same cell_grid, yes. I am doing this to avoid additional tracking overhead and make it so that smart pointers to the derived objects all exist in the same container making them easy to track and call .release() on with no leaks.

The only way I know of that all objects of a class can share the same member is to make that member static and the derived classes pass smart pointers of themselves to the base class for inclusion into the shared 2D vector.

If this is incorrect, bad form, never should be done, etc. then I am open to learn.