Thread: Need help on counting word.

Code:

#include<stdio.h>
#include<conio.h>
#include<string.h>
#include<stdlib.h>
#include <ctype.h>

int main()
{
char str[50];
int words = 0, len=0, i;
int spaces=0;

printf("\n--------------------------------------------------------------------------");
printf("\n\nPROGRAM TO COUNT THE NUMBER OF WORDS, STRING, SPACE IN A GIVEN STRING");
printf("\n\n--------------------------------------------------------------------------");
printf("\n\n\t ENTER A STRING...: ");
//gets(str);
strcpy( str, "a b c d e");



while(str[len]!='\0') len++;

for(i=0;i<=len;i++)
{
        while( isspace( str[i] )) {  spaces++; i++;  }
        {continue;}
        
}
for(i=0;i<len;i++)
{
    while( !isspace( str[i] )) { i++; }
        words++;
        }
printf("\n\t NUMBER OF WORDS IN THE ABOVE SENTENCE IS...: %u", words);
printf("\n\n-------------------------------------------------------");
printf("\n\t NUMBER OF STRING IN THE ABOVE SENTENCE IS...: %u", len);
printf("\n\n-------------------------------------------------------");
printf("\n\t NUMBER OF STRING IN THE ABOVE SENTENCE IS...: %u", spaces);
printf("\n\n-------------------------------------------------------");



getch();
return 0;
}

Hi, everything work fine if i input some number or char.
example: strcpy( str, "a b c d e");
output: 5 word 9 string 4 space
But if i input: strcpy( str, "[space][space][space]");
Output: 3 word 3 string 3 space

This is the error. I should be getting 0 word 3 string 3 space.

Can someone helping me out?

Code:

for(i=0; i<len; i++)
{
    while( !isspace( str[i] ))
    {
        i++;
    }
    words++;
}

With this, you can see that words is counted up no matter what. I think if word switched places with i and then the i part got deleted, the code would work better.