is
void Show_list( const std::vector<int> &List);
equal to
void Show_list( std::vector<int>const &List);
or not?
is
void Show_list( const std::vector<int> &List);
equal to
void Show_list( std::vector<int>const &List);
or not?
If you mean
void Show_list( const std::vector<int> & List);
void Show_list( std::vector<int> const & List);
then yes.
(Note the space between std::vector<int> and const.)
Originally Posted by Adak
i try this
void Show_list( std::vector<int>const & List);
and compile with no error
you mean its different from
void Show_list( std::vector<int> const & List);
?
Upon further testing, it would seem that compilers do accept both syntaxes. Actually, I did not know that, since I have never tried nor looked closely at such code.
Still, whitespace is a good thing, so I would put a space there.
With a few exceptions related to the preprocessor, white space in C++ is only significant for token separation. And ">const" is already two tokens, whether there's a space there or not, because symbols and letters never combine.
All the buzzt!
CornedBee
"There is not now, nor has there ever been, nor will there ever be, any programming language in which it is the least bit difficult to write bad code."
- Flon's Law
