Thread: Yes/No in a loop

Here is part of my program that im having issues with. I know it still needs work and im not done, but on my loop, how can i get it to stop with a "n" or "N" selection? should i get rid of the for loop completely?

Code:

int k;
     int choice;
     char selection;
     
     cout <<"You can make up to 8 single order selections"<<endl;
     cout <<"Do you want to make a selection Y/y(Yes), N/n(No):";
     cin >> selection;
     
     if(selection == 'y'||selection == 'Y')
     {
        for(k=0;k<8;k++){
        cout<<"Enter item number: ";
        cin >> choice;
        cout<<"Select another item Y/y(Yes), N/n(No): ";
        cin >>selection;
     
     switch(choice)
     {
          case 1: m.menuitem[k]="Plain Egg";
               m.menuprice[k]=1.45;
               break;
          case 2: m.menuitem[k]="Bacon and Egg";
               m.menuprice[k]=2.45;
               break;
          case 3: m.menuitem[k]="Muffin";
               m.menuprice[k]=.99;
               break;
          case 4: m.menuitem[k]="French Toast";
               m.menuprice[k]=1.99;
               break;
          case 5: m.menuitem[k]="Fruit Basket";
               m.menuprice[k]=2.49;
               break;
          case 6: m.menuitem[k]="Cereal";
               m.menuprice[k]=.69;
               break;
          case 7: m.menuitem[k]="Coffee";
               m.menuprice[k]=.50;
               break;
          case 8: m.menuitem[k]="Tea";
               m.menuprice[k]=.75;
               break;
     }
    }}
    else if (selection=='N'||selection=='n')
    cout<<"OK. Good bye."<<endl;
    else 
    cout<<"Invalid selection"<<endl;