Thread: Banking System

Hi everyone, This is david, Good day, we had a project in our cs class, creating a banking system, i already create one, but i am having a problem with some part, i am using turbo c++

The output should be the menu first, with 6 choices

1.open bank account
2. check balance
3.deposit
4.withdraw
5.close bank account
6.exit

the objective is to display this 6 items but first they need to choose number 1 which is the open bank account, if they choose other number, it will come up with error and it will just comeback to the menu that is my first problem, cant do it, second problem after creating a bank account, all the options will be enabled but they cannot create a bank account again, they should close it first

Here is the code that i created

Code:

#include <stdio.h>
#include <dos.h>
#include <stdlib.h>
#include<iostream.h>
#include<conio.h>




void main (void)
{
char name[32];
float bal,x;
int c1,c2;
c2=bal=0;
c1=1;
while (c1 != 0)
{
clrscr();

//heading();
    cout<<"========================================\n";
    cout<<"=Welcome to Gomez Bank=\n";
    cout<<"========================================\n";
    cout<<"1. Open Bank Account\n";
    cout<<"2. Check Balance\n";
    cout<<"3. Deposit\n";
    cout<<"4. Withdraw\n";
    cout<<"5. Close Bank Account\n";
    cout<<"6. Exit\n";
    cout<<"Please enter your transaction: ";

    cin>>c1;
    clrscr();

switch(c1)
{

case 1:

cout<<"\nPlease Enter Your Full Name: ";
gets(name);


clrscr();
do
{
cout<<"\n\n\t\t\tNote 500 is the minimuim deposit";
cout<<"\n\nPlease Enter Your Initial Deposit: ";
cin>>x;
}while(x < 500);
bal = bal + x;


getch();
cout<<"Would you like to do another transaction?\n";
cout<<"1.Confirm 2.Exit\n";
cout<<"Enter your choice: ";
cin>>c2;

if (c2 == 2)
{c1 = 0;
break;}
else if(c2 ==1){
break;
}

case 2:
cout<<"Your current balance is: "<<bal<<"\n";
cout<<"Would you like to do another transaction?\n";
cout<<"1.Confirm 2.Exit\n";
cout<<"Enter your choice: ";
cin>>c2;
if (c2 == 2)
{c1 = 0;}
else;
break;


case 3:
cout<<"Enter the value you would like to deposit: ";
cin>>x;
while(x<=0)
{
cout<<"The value you've entered is invalid. \nPlease try again: ";
cin>>x;
}
bal = bal + x;
cout<<"Would you like to do another transaction?\n";
cout<<"1.Confirm 2.Exit\n";
cout<<"Enter your choice: ";
cin>>c2;
if (c2 == 2)
{c1 = 0;}
else;
break;


case 4:
cout<<"Enter the value you would like to withdraw ";
cin>>x;
//bal - x < 500
while (x > bal || x <=0 || bal - x < 500)
{
cout<<"The value you've entered is invalid. \nPlease try again: ";
cin>>x;
}
cout<<"Would you like to do another transaction?\n";
cout<<"1.Confirm 2.Exit\n";
cout<<"Enter your choice: ";
cin>>c2;
if (c2 == 2)
{c1 = 0;}
else;
bal = bal - x;
break;


case 5:


case 6:
c1 = 0;
break;

}
};

cout<<"\n\n\n\t\tThank you for using Gomez Banking Systems!";
getch();

}

Thanks in advanced, for anyone that can help me

At first learn once and forever that main is structured like this

Code:

int main()
{
      ....
      return 0;
}

Second once and forever lesson , style your code nicely.See hIndent_style .

I would set a counter above switch initialized to zero for example.Now in the cases, i would check if when i enter case 1 this counter is zero.If so everything ok and increment the counter by one.If not i would go back to the menu.
Likewise in all the other cases i would check if the counter is greater than zero.If it is ok.If not, do what you want to handle the error.

How to get back in the menu?
With a do - while loop.
Example
Goal : Write a small program to have as a menu only one choice : Input a positive number.If the user does so print this value to screen .Otherwise (which means if the user inputs zero or a negative number) display the menu again and let him input again.Consider that user types only integers.

Code:

#include <iostream>
using namespace std;

int main()
{
    int input;

    do{
      // Display menu
      cout << "Please, input a positive number" << endl;

      // Read input
      cin >> input;

     // While the user types non positive numbers
     // execute the loop body again
    }while( input <= 0 );

    cout << "Value = " << input << endl;

    return 0;
}

Now that you saw an example, try to modify your code

Also David welcome to the forum

Thanks, i just modify my program, it is working fine now, thanks a lot for the algorithm, but i had a big problem, my cs professor, wants me to do it using functions, i mean, every code in case, needs to have its own function, please help, this is my new code

Code:

#include <stdio.h>
#include <dos.h>
#include <stdlib.h>
#include<iostream.h>
#include<conio.h>


#define OPEN 1
#define DEPOSIT 2
#define WITHDRAW 3
#define BALANCE 4
#define CLOSEACCOUNT 5
#define EXIT 6

int main()
{
//////////////////////Init
char name[64];
bool openBank = false;
double balance = 0;
double d = 0; // custom input
int choice;

bool bQuit = false;
//////////////////////Start
while(bQuit == false)
{
system("cls");

cout <<"\n\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\n";
cout <<"\t\tBANKING SYSTEM"; if(openBank){ cout << "\tName :  \"" << name << "\" Balance : " << balance; }cout  <<"\n";
cout <<"\t[1] Open an Account\n";
cout <<"\t[2] Deposit Transaction\n";
cout <<"\t[3] Withdrawal Transaction\n";
cout <<"\t[4] Balance Inquiry\n";
cout <<"\t[5] Close Account\n";
cout <<"\t[6] Exit\n\n";
cout <<"\tPlease choose: "; cin >> choice;

cout <<"\n\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\n";

Case :

if(choice != OPEN && openBank == false && choice !=CLOSEACCOUNT && choice != EXIT)
{cout <<"\tPlease, open the account first\n";choice = OPEN;}

//////////////////////Command
switch(choice) 
{
//////////////////////////////////////////////////////////////////////////////////////////////////////
case OPEN :
    if(openBank == false){
    cout <<"\tAccount name : ";cin >> name;openBank = true;balance = 0;
    cout <<"\tWell done " << name << "! The Bank System has been opened !!!\n";
    }
    else
    {cout <<"\tYou'll need to close the account first !\n";choice = CLOSEACCOUNT;goto Case;}

break;
//////////////////////////////////////////////////////////////////////////////////////////////////////
case DEPOSIT : d = 0;
while(d < 500){
cout <<"\tEnter the amount to deposit (min 500) : "; cin >> d;if(d < 500)
cout <<"\tYou enter is below the minimum deposit. Please enter again.\n\n";}
balance = balance + d;break;
//////////////////////////////////////////////////////////////////////////////////////////////////////
case WITHDRAW : d = 501;
while(d > 500){
cout <<"\tEnter the amout to withdraw (max 500) : "; cin >> d;if(d > 500)
cout <<"\tThe maximum is 500. Please enter again.\n\n";
if(balance - d < 0) {d = 501;
cout <<"\tThe value is invalid. Please enter again\n\n";}}balance = balance - d;break;
//////////////////////////////////////////////////////////////////////////////////////////////////////
case BALANCE :
cout<<"\tYour current balance is: "<<balance<<"\n";
cout <<"Please enter to go back to the main menu. ";getch();
break;
//////////////////////////////////////////////////////////////////////////////////////////////////////
case CLOSEACCOUNT :
if(openBank == false)cout <<"The bank is closed. No need to close now.\n\n"; 
else
{
    cout <<"Please [1] to delete Account and [0] to go back to main menu: "; cin >> choice;
    if(choice == 1){name[0] = 0;openBank = false;}
}
break;
//////////////////////////////////////////////////////////////////////////////////////////////////////
case EXIT : bQuit = true; break;
}
//////////////////////////////////////////////////////////////////////////////////////////////////////
//////////////////////End case commands
}
//////////////////////End Bank loop
return 0;
}
//////////////////////End program...

I think you skipped this link.Don't.I would say it's a must.I mean i won't read your code unless you style it properly.

Originally Posted by std10093

Second once and forever lesson , style your code nicely.See hIndent_style .

A will modify for you my own example by the use of functions.I will use one to print the menu, one to read the input and one to print the result.

Code:

#include <iostream>
using namespace std;

void displayMenu(void);
int readInput(int input);
void dipsplayResult(int input);

int main()
{
    int input;

    do{
      displayMenu();
      input = readInput(input);
    }while( input <= 0 );

    dipsplayResult(input);

    return 0;
}


void displayMenu(void)
{
    cout << "Please, input a positive number" << endl;
}
int readInput(int input)
{
    cin >> input;
    return input;
}
void dipsplayResult(int input)
{
    cout << "Value = " << input << endl;
}

Hi guys, i know that it is a mess, because i am just starting to learn how to program, please help me, if anyone , can help me to use functions on every switch cases, Thanks

Turbo C++ is also used frequently in the Phillipines and Pakistan. But I agree with your sentiment.