1. ## Remove leading zeroes

I have a working code that takes a number and its square to check the reverse of the number and see if it matches a reverse of the original square.

Code:
```#include<iostream>
#include<conio.h>
using namespace std;

int reverse(int i)
{
int temp=i, sum=0;
while(temp)
{
sum*=10;
sum += temp%10;
temp/=10;
}
return sum;
}

int square(int i)
{
return i*i;
}

void main()
{
for(int i=1; i<10001; i++)
{
if(i>9)
{
if(i!=reverse(i))
{
if(square(reverse(i))==reverse(square(i)))
{
cout<<"The number "<<i<<" squares to "<<square(i)<<endl;
cout<<"The number "<<reverse(i)<<" squares to "<<square(reverse(i))<<endl;
cout<<endl;
}
}
}
}
getch();
}```
An output answer that would be correct for example:

The number 12 squares to 144
The number 21 squares to 441

However, I want to remove answers with leading zeroes that are included in the output, such like:

The number 20 squares to 400
The number 2 squares to 4

2. First mind that a typical main is like
Code:
```int main()
{
....
return 0;
}```
Also i have to admit that i do not get what is the question.

3. So if the number is devisible by 10, then skip it. That's !(i%10).

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