New to SQLite. Copied a program from a tutorial site to test whether it is working or not!
Code:
#include <iostream>
#include <sqlite3.h>
#include <stdlib.h>
// g++ AccessTableEmployee.cpp -lsqlite3
using namespace std;
static int callback(void *NotUsed, int argc, char **argv, char **azColName)
{
int i;
cout << "Number of args= " << argc << endl;
for(i=0; i<argc; i++)
{
cout << azColName[i] << " = " << (argv[i] ? argv[i] : "NULL") << endl;
}
cout << endl;
return 0;
}
int main(int argc, char **argv)
{
sqlite3 *db; // Declare pointer to sqlite database structure
char *zErrMsg = 0;
// Open Database
int rc = sqlite3_open("Try.db", &db);
if( rc )
{
cerr << "Can't open database: " << sqlite3_errmsg(db) << endl;
sqlite3_close(db);
exit(1);
}
// Select from database
rc = sqlite3_exec(db,"select * from emp", callback, 0, &zErrMsg);
if( rc!=SQLITE_OK )
{
cerr << "SQL error: " << zErrMsg << endl;
sqlite3_free(zErrMsg);
}
// Close
sqlite3_close(db);
return 0;
}
compiled using following command
g++ -o SQL SQLite.cpp
I am getting following error
/tmp/ccxSqt2x.o: In function `main':
SQLTry.cpp: (.text+0xfd): undefined reference to `sqlite3_open'
SQLTry.cpp: (.text+0x114): undefined reference to `sqlite3_errmsg'
SQLTry.cpp: (.text+0x152): undefined reference to `sqlite3_close'
SQLTry.cpp: (.text+0x18a): undefined reference to `sqlite3_exec'
SQLTry.cpp: (.text+0x1d5): undefined reference to `sqlite3_free'
SQLTry.cpp: (.text+0x1e1): undefined reference to `sqlite3_close'
collect2: ld returned 1 exit status
googled for the solution and came across the same solution every where in the from of following command
g++ -o SQL -lsqlite3 SQLite.cpp
But this solution is not working with me!
Any Help Appreciated!
Using GCC on Debian Linux...