Thread: File access problem

Hello.
I'm planning to code a level editor for an old dungeon game, and thought it'd be nice to output the map file contents to the screen to see what's going on.

Code:

#include <iostream.h>
#include <fstream.h>

int main()
{
      ifstream inFile;
      inFile.open("mod0.map");
     
      // skip header  
      inFile.seekg(56);
      
      unsigned char test;
     
      // output "map" of the corridor
      for(int count = 0; count < 24; count++)
     {	
            inFile >> test;
            if(test < 10)
                  cout << 0;
            cout << int(test) << ' ';
      }

      inFile.close();
      return(0);
}

This results in the following output:
02 04 00 00 00 00 00 00 00 00 06 06 00 00 00 00 00 00 00 00 06 04 203 06

Looking at the relevant section in the file using a hex editor gives:
02 04 00 00 00 00 00 00 00 00 0B 06 0B 06 00 00 00 00 00 00 00 00 06 04

Why is it missing the 0x0Bs out? The output I'd expect is:
02 04 00 00 00 00 00 00 00 00 11 06 11 06 00 00 00 00 00 00 00 00 06 04

Any ideas would be much appreciated. I know that 0x0B is a control code, but wouldn't casting it to an int make it display as 11? Thanks.

Sorry, I should have mentioned that I tried that already and it didn't work! I thought this would be really simple, but it's starting to irritate me now

try using int instead of char

You have to use read() to read a binary file. And as Adrianxw says, open with the binary flag.

Code:

   unsigned char test;
   ifstream inFile;
   inFile.open("mod0.map",ios::binary);
   inFile.read(&test,1);

//or read it all at one time with:
   unsigned char test[24];
   ifstream inFile;
   inFile.open("mod0.map",ios::binary);
   inFile.read(test,24);