I have substr working in a for loop, but its missing a matching letter;
Code:
#include <iostream>
#include <string>
using namespace std;
int main()
{
string msg = "apple";
string msg2 = "padlock";
string string_block;
for (int i = 0; i+1<msg.length(); ++i){
string_block = msg.substr((msg[i] == msg2[i]) == 0) ; // second argument of substr is length, not end.
cout << "String Block: " << string_block[i] << endl;
}
return 0;
}
The output;
String Block: p
String Block: p
String Block: l
String Block: l
Process returned 0 (0x0) execution time : 0.000 s
Press any key to continue.
__________________
As you see, the letter 'a' is missing.
This one works;
Code:
#include <iostream>
#include <string>
using namespace std;
int main()
{
string msg = "aapple";
string msg2 = "padlock";
string string_block;
for (int i = 0; i+1<msg.length(); ++i){
string_block = msg.substr((msg[i] == msg2[i]) == 0) ; // second argument of substr is length, not end.
cout << "String Block: " << string_block[i] << endl;
}
return 0;
}
The results;
String Block: a
String Block: a
String Block: p
String Block: l
String Block: e
Process returned 0 (0x0) execution time : 0.000 s
Press any key to continue.
________
But now there is an 'e'.