Problem with two functions in single cout

Code:

`#include<iostream>`

#include<conio.h>

using namespace std;

typedef unsigned long ulong;

long eeuclid(long m, long b, long *inverse){ /// eeuclid( modulus, num whose inv is to be found, variable to put inverse )

/// Algorithm used from Stallings book

long A1 = 1, A2 = 0, A3 = m,

B1 = 0, B2 = 1, B3 = b,

T1, T2, T3, Q;

cout<<endl<<"eeuclid() started"<<endl;

while(1){

cout<<"in loop\n";

if(B3 == 0){

*inverse = 0;

return A3; // A3 = gcd(m,b)

}

if(B3 == 1){

*inverse = B2; // B2 = b^-1 mod m

return B3; // A3 = gcd(m,b)

}

Q = A3/B3;

T1 = A1 - Q*B1;

T2 = A2 - Q*B2;

T3 = A3 - Q*B3;

A1 = B1; A2 = B2; A3 = B3;

B1 = T1; B2 = T2; B3 = T3;

/*

cout<<"here"<<endl;

if( getch() =='q' ) exit(0);

// */

}

cout<<endl<<"ending eeuclid() "<<endl;

}

int main(){

long a, b, c, d=0, e, inverse = 0;

int ch;

cout<<"Preparing extended Euclid ---> "<<endl;

cout<<"m >> ";

cin >> a;

cout<<"b >> ";

cin >> b;

cout<<"gcd("<<a<<","<<b<<") = "<<eeuclid(a, b, &inverse);

cout<<" and inverse = "<<inverse<<endl;

cout<<endl<<"Press q to quit ... "<<endl;

return 0;

}

In the above code, in the main() function, if
Code:

`cout<<"gcd("<<a<<","<<b<<") = "<<eeuclid(a, b, &inverse);`

cout<<" and inverse = "<<inverse<<endl;

is replaced by
Code:

`cout<<"gcd("<<a<<","<<b<<") = "<<eeuclid(a, b, &inverse)<<" and inverse = "<<inverse<<endl;`

the value of inverse prints out as 0, even though single stepping through the code and examining the value in memory shows that the variable inverse has the correct value

Why is that??

FYC: also posted here

Problem with two functions in single cout - Dev Shed