Hi ,
I have some questions about memory allocation.
When we use malloc function as:
Eg.
Does this mean that we are allocating memory space to data type "int" which is 7 times?Code:malloc(7*(size of(int)));
Also as far as I know malloc function doesnot initialize the objects using any constructor nor it returns any type except for void.
Do we have to define malloc function inside the main() function?
I hope i am clear
thanks
All of these questions could be answered just by looking up "man pages malloc" on google. malloc() is a staple of C, but the "new" keyword is what you should use in c++. No you don't have to define malloc() inside the main. It is provided by including <stdlib.h> (for C) or <cstdlib> (for C++). Like I said though, "new" is meant for C++ use.
Finally malloc returns a pointer to a chunk of memory dictated by 7*sizeof(int). So it finds what size an int is on your computer, you're multiplying by 7, so it will return a pointer to a chunk of memory which can store 7 integers. There is a page about malloc() and casting here: FAQ: Casting malloc?
It can be hard to find information at first, but get used to googling.
EDIT:
A bit more nuanced than what I was willing to go:
http://www.codeproject.com/Articles/...ix-them-is-sin
Last edited by Ocifer; 02-02-2012 at 11:32 AM.
W7, Ubuntu -- mingw, gcc, g++, code::blocks, emacs, notepad++
Also, it should be: sizeof() and NOT size of()
ONE WORD.
W7, Ubuntu -- mingw, gcc, g++, code::blocks, emacs, notepad++
