Thread: switch

Code:

void foo()
{
	unsigned int x,y;
	unsigned int n= rand();
	switch(n%4)
	{
		for(x=0;x<1000;++x)
		{
			for(y=0;y<1000;++y)
			{
				case 0:
					//special instructions
					break;
				case 1:
					//special instructions
					break;
				case 2:
					//special instructions
					break;
				case 3:
					//special instructions
					break;
			}
		}
	}
}

in the code above, are switch statement cases evaluated in the inner loop? i'm thinking vs should be smart enough the answer is 'no', but i can't think of a way to verify it empirically, so i pose the question here.

thanks.

You can't think of a way to verify it empirically? What about... trying it? Or did I get your question just wrong?

it seems perhaps you may not have appreciated the nuance of my problem.

nevermind. it seems as though despite this being a useful way to write a switch, it skips the block before the first case.

evidently, yes.