Thread: How to input char variables in the same line?

I have to make this program: I have to enter x number of letters in the same line and the program has to count vowels and consonants. So I've made a program that does all that except I don't know how to enter the letters in the same line.
P.S. I know this is a basic c++ but couldn't find a better place to post this.

Code:

#include <iostream>


using namespace std;


int main()
{
    char letter;
    int vow = 0;
    int con = 0;
    cout << "Enter the letters. To end the input insert a: " << endl;
    do
    {
        cin >> letter;
        if (letter=='a'||letter=='e'||letter=='i'||letter=='o'||letter=='u'||letter=='A'||letter=='E'||letter=='I'||letter=='O'||letter=='U')
        {
            vow++;
        }else
        {
            con++;
        }
    }while(letter!='a');
    cout << "Number of vowels is: " << vow << endl;
    cout << "Number of consonants is: " << con << endl;
    return 0;
}

No, I have to enter random number of letters and the input ends with little letter a, for example:

Input: b i G h e K p a (and when I type in that last letter which has to be "a" it guves me a number of vowels and consonants that I typed in)

Output: Number of vowels is: 3. Number of consonants is: 4.

Then what does letters in the same line mean?

Like I just wrote it.
RIGHT:
Input: b [ENTER] i [ENTER] G [ENTER] ....
WRONG:
Input:
b [ENTER]
i [ENTER]
G [ENTER] ....

... or without having to press ENTER doesn't matter it just has to get letters in the same line and has to end with a letter "a" not "A".

You have to input a few letters (not sentences! ... and in the same line) and the input finishes when you enter "a", then you get a number of vowels and consonants as the result.

Have you tried just running what you have, with the input in the format that you expect?

Even if you are reading input character by character, that in no way implies that the format of the input is one character per line.

What I need is when I type in first letter for example "b" and press ENTER to stay in the same line, don't want to go to a new line, even though I don't know if that's even possible.

Originally Posted by whiteflags

You're utterly wrong.

OP, the code already does what you want. To use your example all you have to do is type

b i G h e K p a

And then press enter. The loop will still stop at 'a'. Since cin is line buffered, though, you will have to press enter to get things to happen (that's usually what buffered means -- how many keys you have to press before something happens). You can press enter whenever you're ready. This is what I was trying to say in my earlier post. Just because you read one character at a time, it doesn't mean the characters have to be on separate lines.

I get what you want to say but when I press "a" the input MUST stop and the program goes to output, in other words, it cannot allow me to input any more letters after "a".