Thread: doubt

Consider this

123 / 10 = 12
123 % 10 = 3

Originally Posted by Salem

Consider this

123 / 10 = 12
123 % 10 = 3

but the program is not limited to a 3 digit number.
actually, i want to write a code for output:

....1
...1 1
..1 2 1
.1 3 3 1
1 4 6 4 1

the dots represent spaces(spaces were not coming,it was becoming left indented so i put dots)
these r powers of 11,with alternate space & digits

Is it really powers of 11, or Pascal's Triangle?
Pascal's triangle - Wikipedia, the free encyclopedia

Because strictly powers of 11 breaks down after a few rows.

Well "we" could try reading the algorithm description on wikipedia, then attempt some code to calculate the current row based on the previous row.

Eg.

Code:

int oldRow[10] = { 1 };
int newRow[10] = { 0 };  // make this contain { 1, 1, 0, 0, 0, 0, 0, 0, 0, 0 }

Then with some more iterations of the code.

Code:

int oldRow[10] = { 1, 3, 3, 1 };
int newRow[10] = { 0 };  // make this contain { 1, 4, 6, 4, 1, 0, 0, 0, 0, 0 }

I mean, once you have the algorithm in place, and an initialised row to work from, the rest is pretty easy.